Algebraic Identities & Expressions

Expert Answer & Key Takeaways

Master standardized algebraic identities, (x+1/x)(x + 1/x) models, and 'Value Putting' strategies to solve complex expressions in seconds.

Model 1: Standard Algebraic Identities

  • (a+b)2=a2+b2+2ab(a+b)^2 = a^2 + b^2 + 2ab
  • (ab)2=a2+b22ab(a-b)^2 = a^2 + b^2 - 2ab
  • a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b)
  • (a+b)3=a3+b3+3ab(a+b)(a+b)^3 = a^3 + b^3 + 3ab(a+b)
  • a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)
  • a3+b3+c33abc=(a+b+c)(a2+b2+c2abbcca)a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2+b^2+c^2-ab-bc-ca)
  • Special Case: If a+b+c=0a+b+c=0, then a3+b3+c3=3abca^3+b^3+c^3 = 3abc.

Model 2: The Value Putting Strategy

Convert abstract algebra into simple arithmetic by assuming values for variables.

  • Rule: Never let the denominator become zero.
  • Golden Values: Try a=1,b=1,c=0a=1, b=1, c=0 or a=2,b=1,c=3a=2, b=1, c=-3.
  • Symmetry: If all variables are symmetric in the expression, try a=b=ca=b=c.

Model 3: Advanced Identities (x + 1/x)

  • If x+1/x=kx + 1/x = k, then x2+1/x2=k22x^2 + 1/x^2 = k^2 - 2
  • If x1/x=kx - 1/x = k, then x2+1/x2=k2+2x^2 + 1/x^2 = k^2 + 2
  • If x+1/x=1x + 1/x = 1, then x3=1x^3 = -1
  • If x+1/x=sqrt3x + 1/x = sqrt{3}, then x6=1x^6 = -1

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