Probability

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1. Basic Definition

Probability is the measure of the likelihood of an event occurring.

P(E)=Number of Favourable OutcomesTotal Number of Possible OutcomesP(E) = \frac{\text{Number of Favourable Outcomes}}{\text{Total Number of Possible Outcomes}} or P(E)=n(E)n(S)P(E) = \frac{n(E)}{n(S)}

Where n(S)n(S) is the Sample Space.

Example:

Q: Find the probability of getting a Head when tossing a coin.
Solution: Total Outcomes (SS) = {H, T} n(S)=2\to n(S)=2.
Favourable (EE) = {H} n(E)=1\to n(E)=1.
P(H)=1/2P(H) = 1/2.

2. Limits of Probability

The probability of an event lies between 0 and 1 (inclusive).

0P(E)10 \le P(E) \le 1

  • P(E)=0P(E) = 0: Impossible Event (e.g., Rolling a 7 on a standard die).
  • P(E)=1P(E) = 1: Certain Event (e.g., Sun rising in the East).
  • P(E)+P(not E)=1P(E) + P(\text{not } E) = 1 (Complementary Events).

3. Coins Concepts

  • 1 Coin: {H, T} 21=2\to 2^1 = 2.
  • 2 Coins: {HH, HT, TH, TT} 22=4\to 2^2 = 4.
  • 3 Coins: {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} 23=8\to 2^3 = 8.

Trick: For 'At least 1 Head', use 1P(No Head)1 - P(\text{No Head}).

Example:

Q: 3 coins are tossed. Prob of getting at least 1 Head?
Solution: Total = 8. No Head (TTT) = 1 case.
P(At least 1 H)=11/8=7/8P(\text{At least 1 H}) = 1 - 1/8 = 7/8.

4. Dice Concepts

  • 1 Die: {1, 2, 3, 4, 5, 6} 61=6\to 6^1 = 6.
  • 2 Dice: (1,1) to (6,6) 62=36\to 6^2 = 36.

Sum on 2 Dice (Shortcut):
Min Sum 2 (1 way), Max Sum 12 (1 way).
Sum 7 has max ways (6 ways).
Pattern: 1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1 (for sums 2 to 12).

5. Playing Cards

Total Cards = 52.

  • Suits (13 each): Spades (♠), Clubs (♣) [Black]; Hearts (♥), Diamonds (♦) [Red].
  • Face Cards: King, Queen, Jack (3 per suit ×\times 4 = 12 total).
  • Honours: A, K, Q, J.

6. Balls & Marbles (AND/OR Rules)

  • AND Rule (Multiplication): Event A AND Event B occur P(A)×P(B)\to P(A) \times P(B). (Independent events).
  • OR Rule (Addition): Event A OR Event B occur P(A)+P(B)\to P(A) + P(B) (Mutually Exclusive).

Selection: Use Combinations (nCr{}^{n}C_{r}).
P(Selection)=Favourable CombinationsTotal CombinationsP(\text{Selection}) = \frac{\text{Favourable Combinations}}{\text{Total Combinations}}.
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