Ratio & Proportion

The foundation of Arithmetic. Master the art of 'Balancing Ratios', the C&D Rule, and the 'Coins Concept' to solve distribution problems instantly.

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1. Balancing Ratios (Zig-Zag Method)

To combine A:BA:B and B:CB:C into A:B:CA:B:C.

  • Method: If A:BA:B is 2:32:3 and B:CB:C is 4:54:5.
  • Make 'B' common. Multiply first by 4, second by 3.
  • Zig-Zag: (2×4):(3×4):(3×5)=8:12:15(2 \times 4) : (3 \times 4) : (3 \times 5) = 8 : 12 : 15.

Example:

Q: If A:B=2:3A:B=2:3 and B:C=5:7B:C=5:7, find A:B:CA:B:C.
Solution: A:B=2:3A:B = 2:3. B:C=5:7B:C = 5:7.
Multiply top by 5, bottom by 3.
10:15:2110 : 15 : 21.

2. Types of Proportions

Basic formulas for a:b::c:da:b::c:d.

  • Mean Proportional between aa and bb: ab\sqrt{ab}.
  • Third Proportional to a,ba, b: b2/ab^2/a.
  • Fourth Proportional to a,b,ca, b, c: bc/abc/a.

Example:

Q: Find Third Proportional to 4 and 6.
Solution: b2/a=62/4=36/4=9b^2/a = 6^2/4 = 36/4 = 9.

3. Componendo & Dividendo (C&D Rule)

Used when a/b=c/da/b = c/d.

  • Rule: a+bab=c+dcd\frac{a+b}{a-b} = \frac{c+d}{c-d}.
  • Shortcut: If you see x+axa=b\frac{x+a}{x-a} = b, imply x/a=(b+1)/(b1)x/a = (b+1)/(b-1).

Example:

Q: If x+5x5=73\frac{x+5}{x-5} = \frac{7}{3}, find x.
Solution: By C&D: x/5=(7+3)/(73)=10/4=5/2x/5 = (7+3)/(7-3) = 10/4 = 5/2.
x=25/2=12.5x = 25/2 = 12.5.

4. Coins & Value Concept

Standard Exam Pattern.

  • Formula: Value=Denomination×Number of Coins\text{Value} = \text{Denomination} \times \text{Number of Coins}.
  • Tip: Convert everything to smallest unit (Paise) to avoid decimals.

Example:

Q: Bag has Rs 1, 50p, 25p coins in ratio 2:3:4. Total Rs 180. Find 50p coins.
Solution: Values: 2(100):3(50):4(25)=200:150:100=4:3:22(100) : 3(50) : 4(25) = 200:150:100 = 4:3:2.
Sum ratios: 9 units = 18000p. 1 unit = 2000.
Value of 50p = 3×2000=6000p3 \times 2000 = 6000p. Coins = 6000/50=1206000/50 = 120.

5. Income-Expenditure Ratio

Logic: IncomeExpenditure=Savings\text{Income} - \text{Expenditure} = \text{Savings}.

  • Cross-Product Method: If Ratio of Income is A:BA:B, Exp is C:DC:D, and Savings are S1,S2S_1, S_2.
  • (ADBC)x=(CS2DS1)(AD - BC)x = (CS_2 - DS_1). Use this to find 'x' unit value directly.

Example:

Q: Income ratio 3:2, Exp ratio 5:3, Savings Rs 1000 each. Find Income.
Solution: Cross: (3×3)(2×5)=910=1(3 \times 3) - (2 \times 5) = 9-10 = -1.
Savings: (5×1000)(3×1000)=2000(5 \times 1000) - (3 \times 1000) = 2000.
1 unit = 2000. Income A=3×2000=6000A = 3 \times 2000 = 6000.
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