Time, Speed & Distance

The heaviest topic in arithmetic. Mastering Relative Speed and Ratio Methods is key to solving Trains and Boats problems without long equations.

1. The Ratio Method (Constant Distance)

When Distance is same.

  • Rule: S1:S2=a:bтАЕтАКтЯ╣тАЕтАКT1:T2=b:aS_1 : S_2 = a : b \implies T_1 : T_2 = b : a.
  • Use for 'Late/Early' problems to find exact time difference units.

Example:

Q: Speed 34th, reaches 20 min late.
Solution: Speed 4:3. Time 3:4. Gap 1u = 20m.
Actual Time (3u) = 60 min.

2. Average Speed

Not (S1+S2)/2(S_1+S_2)/2.

  • Case A (Equal Distances): Harmonic Mean 2xyx+y.
  • Case B (Equal Time): Arithmetic Mean x+y2.
  • General: Total Distance / Total Time.

Example:

Q: Goes 60 kmph, returns 40 kmph.
Solution: 2 imes 60 imes 40100 = 48 kmph.

3. Relative Speed

Moving bodies.

  • Opposite Direction: Add Speeds (S1+S2S_1 + S_2).
  • Same Direction: Subtract Speeds (S1тИТS2S_1 - S_2).
  • Used for Meeting Times and Overtaking.

Example:

Q: A (40) and B (50) move towards each other. Gap 180km.
Solution: Rel Speed = 90. Time = 18090 = 2 hrs.

4. Trains (Length Logic)

Distance is never zero.

  • Crossing Pole: Dist = Train Length (LTL_T).
  • Crossing Platform/Train: Dist = LT+LPL_T + L_P.
  • Speed is Relative Speed if object moves.

Example:

Q: Train (100m) crosses Bridge (200m) in 20s.
Solution: Total Dist 300m. Speed = 30020 = 15 m/s = 54 kmph.

5. Boats & Streams

River flow adds or subtracts.

  • Downstream (Along): B+SB + S.
  • Upstream (Against): BтИТSB - S.
  • Formulas: B=(D+U)/2B = (D+U)/2, S=(DтИТU)/2S = (D-U)/2.

Example:

Q: Down 20 kmph, Up 10 kmph.
Solution: Boat Speed = 20+102 = 15. Stream = 5.

6. Linear Races & Head Starts

Giving a 'start'.

  • Start of distance: A beats B by xx meters.
  • Start of time: A beats B by tt seconds.
  • Dead Heat: Both reach at same time.

Example:

Q: A beats B by 10m in 100m race.
Solution: Ratio Dist A:B = 100:90 = 10:9. Speed Ratio is same.

7. Circular Motion

Meeting on track.

  • First Meeting: L/SrelL / S_{rel}.
  • Meeting at Start: LCM(T1,T2T_1, T_2).
  • Distinct Points: S1/S2S_1/S_2 reduced ratio (a/b)(a/b). Points = a+ba+b (Opp) or тИгaтИТbтИг|a-b| (Same).

Example:

Q: Speeds 3:2, Circular Track. How many distinct meeting points?
Solution: Opposite: 3+2=53+2=5. Same Dir: 3тИТ2=13-2=1.