Simple & Compound Interest

Money makes money. Master the 'Effective Rate' method for CI ($x+y+xy/100$) and the 'Difference Formula' to solve 2-year and 3-year problems accurately.

1. SI vs CI (The Core Difference)

SI is Interest on Principal ONLY. CI is Interest on Principal + Interest on Interest.

  • SI: Rate RR% per year. Total Interest for TT years = R├ЧT%R \times T \%.
  • CI: Successive % Change. Use x+y+xy/100x+y+xy/100 for 2 years.

Example:

Q: Find CI on Rs 1000 for 2 years at 10%.
Solution: Effective Rate: 10+10+(10├Ч10)/100=21%10+10+(10\times10)/100 = 21\%.
21%21\% of 1000 = 210.

2. The Difference Formulas (Golden Rules)

Direct shortcut for Difference (DD) between CI and SI.

  • 2 Years: D=P(R/100)2D = P (R/100)^2.
  • 3 Years: D=P(R/100)2(3+R/100)D = P (R/100)^2 (3 + R/100).

Example:

Q: Diff between CI and SI for 2 years at 5% is Rs 25. Find P.
Solution: 25=P(5/100)225 = P (5/100)^2.
25=P(1/400)25 = P (1/400). P=10000P = 10000.

3. The 'Times' Concept (N Times)

Sum becomes N times in T years.

  • SI: Linear Growth. If it doubles (gain 100%) in 5 yrs, it triples (gain 200%) in 10 yrs.
  • CI: Exponential Powers. If it doubles (212^1) in 5 yrs, it becomes 8 times (232^3) in 5├Ч3=155 \times 3 = 15 yrs.

Example:

Q: Money doubles in 4 years at CI. When 8 times?
Solution: 21тЖТ42^1 \to 4 yrs.
8=23тЖТ4├Ч3=128 = 2^3 \to 4 \times 3 = 12 yrs.

4. Effective Rate for CI (Successive)

Best for 2-3 years.

  • 2 Years: 2R+R2/1002R + R^2/100. Example 10% тЖТ\to 21%.
  • 3 Years: 3R.3R2R33R.3R^2 R^3 (Pascal's Triangle 3:3:1 logic). Example 10% тЖТ\to 33.1%.

Example:

Q: CI on 5000 at 2% pa for 2 years.
Solution: Eff Rate: 2+2+(4/100)=4.04%2+2 + (4/100) = 4.04\%.
4.04%4.04\% of 5000 = 202.

5. Half-Yearly & Quarterly Compounding

Adjust Rate and Time.

  • Half-Yearly: Rate becomes R/2R/2, Time becomes 2T2T.
  • Quarterly: Rate becomes R/4R/4, Time becomes 4T4T.

Example:

Q: 20% pa compounded half-yearly for 1 year.
Solution: New Rate = 10%. New Time = 2 cycles.
Eff Rate = 10+10+1=21%10+10+1 = 21\%.

6. Installments (EMI)

Present Value Concept.

  • SI Installment: Debt A=x+(x+int)+...A = x + (x + \text{int}) + ... (Reverse Order).
  • CI Installment: P=I(1+r)+I(1+r)2P = \frac{I}{(1+r)} + \frac{I}{(1+r)^2}.

Example:

Q: Loan 2100 at 10% CI. 2 Annual Installments.
Solution: 10% is 1/10. Installment ratio: 10:1110:11 and 100:121100:121.
Scale first to 121: 110:121110:121. Sum P = 210. Sum I = 242.
210тЖТ2100210 \to 2100. Installment = 1210.