DEBUG_INFO: title=Simple & Compound Interest, type=object, isArray=, length=6
SI is Interest on Principal ONLY. CI is Interest on Principal + Interest on Interest.
SI: Rate R R% R per year. Total Interest for T T T years = R ├Ч T % R \times T \% R ├Ч T % .CI: Successive % Change. Use x + y + x y / 100 x+y+xy/100 x + y + x y /100 for 2 years.
Example:
Q: Find CI on Rs 1000 for 2 years at 10%.
Solution: Effective Rate: 10 + 10 + ( 10 ├Ч 10 ) / 100 = 21 % 10+10+(10\times10)/100 = 21\% 10 + 10 + ( 10 ├Ч 10 ) /100 = 21% . 21 % 21\% 21% of 1000 = 210. Direct shortcut for Difference (D D D ) between CI and SI.
2 Years: D = P ( R / 100 ) 2 D = P (R/100)^2 D = P ( R /100 ) 2 .3 Years: D = P ( R / 100 ) 2 ( 3 + R / 100 ) D = P (R/100)^2 (3 + R/100) D = P ( R /100 ) 2 ( 3 + R /100 ) .
Example:
Q: Diff between CI and SI for 2 years at 5% is Rs 25. Find P.
Solution: 25 = P ( 5 / 100 ) 2 25 = P (5/100)^2 25 = P ( 5/100 ) 2 . 25 = P ( 1 / 400 ) 25 = P (1/400) 25 = P ( 1/400 ) . P = 10000 P = 10000 P = 10000 .Sum becomes N times in T years.
SI: Linear Growth. If it doubles (gain 100%) in 5 yrs, it triples (gain 200%) in 10 yrs.CI: Exponential Powers. If it doubles (2 1 2^1 2 1 ) in 5 yrs, it becomes 8 times (2 3 2^3 2 3 ) in 5 ├Ч 3 = 15 5 \times 3 = 15 5 ├Ч 3 = 15 yrs.
Example:
Q: Money doubles in 4 years at CI. When 8 times?
Solution: 2 1 тЖТ 4 2^1 \to 4 2 1 тЖТ 4 yrs. 8 = 2 3 тЖТ 4 ├Ч 3 = 12 8 = 2^3 \to 4 \times 3 = 12 8 = 2 3 тЖТ 4 ├Ч 3 = 12 yrs.Best for 2-3 years.
2 Years: 2 R + R 2 / 100 2R + R^2/100 2 R + R 2 /100 . Example 10% тЖТ \to тЖТ 21%.3 Years: 3 R .3 R 2 R 3 3R.3R^2 R^3 3 R .3 R 2 R 3 (Pascal's Triangle 3:3:1 logic). Example 10% тЖТ \to тЖТ 33.1%.
Example:
Q: CI on 5000 at 2% pa for 2 years.
Solution: Eff Rate: 2 + 2 + ( 4 / 100 ) = 4.04 % 2+2 + (4/100) = 4.04\% 2 + 2 + ( 4/100 ) = 4.04% . 4.04 % 4.04\% 4.04% of 5000 = 202. Adjust Rate and Time.
Half-Yearly: Rate becomes R / 2 R/2 R /2 , Time becomes 2 T 2T 2 T .Quarterly: Rate becomes R / 4 R/4 R /4 , Time becomes 4 T 4T 4 T .
Example:
Q: 20% pa compounded half-yearly for 1 year.
Solution: New Rate = 10%. New Time = 2 cycles. Eff Rate = 10 + 10 + 1 = 21 % 10+10+1 = 21\% 10 + 10 + 1 = 21% . Present Value Concept.
SI Installment: Debt A = x + ( x + int ) + . . . A = x + (x + \text{int}) + ... A = x + ( x + int ) + ... (Reverse Order).CI Installment: P = I ( 1 + r ) + I ( 1 + r ) 2 P = \frac{I}{(1+r)} + \frac{I}{(1+r)^2} P = ( 1 + r ) I тАЛ + ( 1 + r ) 2 I тАЛ .
Example:
Q: Loan 2100 at 10% CI. 2 Annual Installments.
Solution: 10% is 1/10. Installment ratio: 10 : 11 10:11 10 : 11 and 100 : 121 100:121 100 : 121 . Scale first to 121: 110 : 121 110:121 110 : 121 . Sum P = 210. Sum I = 242. 210 тЖТ 2100 210 \to 2100 210 тЖТ 2100 . Installment = 1210.